8x^2-92x-156=0

Solution for 8x^2-92x-156=0 equation:

8x^2-92x-156=0

a = 8; b = -92; c = -156;
Δ = b2-4ac
Δ = -922-4·8·(-156)
Δ = 13456
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{13456}=116$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-92)-116}{2*8}=\frac{-24}{16}
=-1+1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-92)+116}{2*8}=\frac{208}{16}
=13
$